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Code here:

package main

import "fmt"

func my_func(do_run bool) bool {
	do_run = !do_run // Just to test if I may modify an input param
	return do_run
}

func main() {
	run_param := false // Or true
	run_now := my_func(run_param)
	fmt.Println(run_now)
}

Code here:

package main

import "fmt"

func main() {
	val_max_index := 1000                   // Try val 1,10,100,1000,10000,100000 (with val_num_remainder_of_zeroes_wanted=0)
	val_num_remainder_of_zeroes_wanted := 0 // Try val 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16 (with val_max_index=1000)

	remainder_of_zero_cnt := 0

	line_entries_per_line_max := 10 // [2..
	is_running := true
	index := 1                   // Division by zero not legal, start at 1, but print a dot for zero:
	fmt.Print(0, ":\t.", "\t")   // Head of line, start with 0: and dot
	line_vals_this_line_cnt := 1 // Done the first (the dot)

	for is_running { // until index max or reached specified number of zero counts
		remainder := val_max_index % index // remainder after modulo division
		if remainder == 0 {
			remainder_of_zero_cnt++
			if val_num_remainder_of_zeroes_wanted != 0 {
				if remainder_of_zero_cnt == val_num_remainder_of_zeroes_wanted {
					is_running = false
					// Delay printing until after remainder has been printed
				} else {
					// Don't stop now
				}
			} else { // val_num_remainder_of_zeroes_wanted=0
				// Stop when index reaches max
			}
		} else {
			// Not zero now
		}

		fmt.Print(remainder, "\t")

		line_vals_this_line_cnt++

		if line_vals_this_line_cnt != line_entries_per_line_max {
			// More values to print, no new line
		} else {
			line_vals_this_line_cnt = 0
			fmt.Print(" (", remainder_of_zero_cnt, ")\n", index+1, ":\t")
			// End of line, new line with new Head of line, like 10: .. ..  (15)
		}

		if is_running == true {
			is_running = index < val_max_index
			index++
		} else {
			fmt.Print("\n", "Reached num zeroes: ", remainder_of_zero_cnt, " N:", index, " ")
		}
	}
	fmt.Print("\n", "Finally num zeroes: ", remainder_of_zero_cnt)
}

The code basically counts up how many times the remainder after an integer division is zero (no remainder, is divisible), starting at 1 going up to N. The example then does 1000 remainder divsion (%) by 1 up to 1000%1000 (more below). There are some interesting properties that show up there, see references below. There are two things you could easily change, for two test scenarios, the red and the green (somewhat reflected by the code’s colour, above).

In the red test sequence I kept val_num_remainder_of_zeroes_wanted as zero and modified val_max_index as 1,10,100,1000,10000 and saw remainder_of_zero_cnt as 1,4,9,16,25,36. This is actually the first squares: 1*1, 2*2, 3*3, 4*4, 5*5 and 6*6. I wasn’t allowed run time for higher numbers by the Go Playground. (10000 may or may not cause «process took too long» from the Playground server..).

In the green test sequence I kept val_max_index as 1000 and modified val_num_remainder_of_zeroes_wanted as 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16 and I got the list of «Reached num zeroes» as 1,2,4,5,8,10,20,25,40,50,100,125,200,250,500,1000. This simply is the list of the possible divisors for 1000.

I found some papers discussing some of this. Like these:

• Samtliga positiva delare till talen 1 t.o.m. 1000 (all positive factors of the numbers [1..1000]
• How many divisiors are there for number 1000?
• Surprising Patterns in the Square Numbers (1, 4, 9, 16…)

However, it’s the basic look and feel of the code that matters here, not the funny results of the arithmetics. I am used to always showing the else in an if clause; it may clutter the code now, but its intention is clearer. Also since I was used to doing safety critical code at work, there this would be required.